What this answers
This calculator answers "given several p-values from tests I ran together, how should each one be adjusted so my overall false-positive rate across the whole family stays controlled?" Testing many hypotheses without any correction inflates the chance that at least one comes back significant purely by chance.
How it is calculated
Each p-value is multiplied by the family size (the total number of tests being considered together), capped at 1. Equivalently, you can compare each raw p-value against an adjusted alpha threshold of alpha divided by the family size. Both views describe the same correction; this calculator shows both. Bonferroni does not decide which tests belong in the family; you must declare that yourself, and it can differ from the number of p-values you happen to enter here if you know the true family is larger.
Worked example
For raw p-values of .01 and .03 with a family size of 2, the adjusted p-values are .02 and .06. At the conventional .05 threshold, the first comparison remains significant after correction while the second, originally below .05, no longer is, exactly the kind of result an uncorrected analysis would have missed.
Assumption audit
What this result does not mean
Surviving Bonferroni correction means a result remains significant even under this conservative adjustment, a fairly strong claim; failing to survive it does not mean there is no real effect, since Bonferroni is deliberately conservative and can miss real, smaller effects, especially as the family size grows large.
Limitations
Bonferroni is the simplest and most conservative common correction; for many post-hoc comparisons following an omnibus test, Holm's step-down method (used automatically by the Dunn Post-Hoc Test on this site) offers more power while still controlling the same family-wise error rate.