What this answers
This test answers the same underlying question as Shapiro-Wilk, "is this sample consistent with a normal distribution?", but weights departures in the tails of the distribution more heavily than departures near the center, making it especially sensitive to occasional extreme values.
How it is calculated
The statistic compares your sorted, standardized values against the normal cumulative distribution function at every point, with more weight given to points near the extremes. Because the mean and standard deviation used to standardize your data are themselves estimated from the same sample, this calculator applies Stephens' (1974) small-sample correction factor to the raw statistic before computing a p-value, using the standard D'Agostino and Stephens (1986) piecewise approximation formula.
Worked example
The published critical value for a 5% significance level is a corrected statistic of about .752; plugging that value into the D'Agostino-Stephens formula gives a p-value of almost exactly .05, confirming the formula's calibration against the standard reference table. A roughly evenly spaced sample, like the default example above, produces a small statistic and a large p-value, consistent with no detected evidence against normality.
Assumption audit
What this result does not mean
A non-significant result does not prove normality, only that this particular test, which is especially attentive to tail behavior, did not detect enough evidence against it. A significant result flags a departure, most often in the tails given how this test weights deviations, but does not by itself say the departure is too large to matter for whatever analysis comes next.
Limitations
This calculator requires at least 8 values; below that, both the correction factor and p-value approximation lose their calibration. For a second opinion using a different weighting of evidence across the whole distribution rather than emphasizing the tails, see the Shapiro-Wilk Normality Test.